So why do we have double casting the below code, so you have minus three under intercessor?
First, you are bypassing it with unsigned and then you are getting that gas, you do it unsigned long.
So why do we need the oil?
Gas under a single gas is sufficient here.
So the reason for this is the negative sign in my study into Hazard is first converted into an unsigned
and with signed extension to whatever size and side in this.
So it will always be a little bit in.
The second guessed will cost up to the size of an unsigned along with zero extension.
So first one is passing it to the second one is casting it to.
64 bit or 32, depending on the architecture.
So this is a we are only trying to test the reason is we are only trying to test this on the overflow,
but all.
Excited about architecture, 64 bit architecture on 64 bit Decalogue, the amount of time to offload
what you can offer, learn if the value of it is a thousand, but a lot of light 49 days.
So we are only first testing this for 32 architectures.
So Unsign will first convert this into a bit and then we'll convert it into.
Started a bit of it, depending on the operation.
So one more example.
Guess that would put out this photo.
You know what is here, so I'm subtracting minus one.
With initial deficit, this is double that level, Ms.
Gaster, that Cassard and this is only one step geston is the output of this program.
Will be will it be same on 60 for whatever 32 bit?
So you can see the difference here.
This is why it is double Tadcaster.
This is when it is only that gas the once.
This is 300 to 250.
Just seventy five thousand militants abducted by one.
So a terrible line.