No, no, we go to the base.
Let's try to find out the size of this.
Amount.
How do you determine the amount of anticipation that may be utilized so it base address is the half
the information we just needed?
You also need to get the size of the device to get the size of the device.
What do you have to do is you have to see if the additional value of the base and then you have to write
all the ones to the particular register.
Then you read it back and finally you have to piece together what is going to value what you have seen.
So the amount of memory which is used by the particular device can be determined at masking the information.
So you have to perform a bitwise note of whatever the value you have received here.
So when you write all, once you read it, you have to perform that a note on that particular result
and then increment the value by one.
Then you'll be getting that amount of space used by that particular device.
So.
Now, we have seen the colistin.
You are eating a lot of this stuff I have for the 60 vote majority to finally get the address.
I know all they have to do is you have to literally consider the 60 40 and I remember you.
You have to write all F's.
The location, because of the 64 bit, I don't know the location, the new.
That particular location.
No, you're right, though, you destroy the resale value, so we have already talked one end of this
to restore the original value and then.
Printing whatever you ordered and then you perform.
The masking, so you may be Glazerman.
And you can hear you have to clear this list for this, but if I have to say that and then you add this
one, this is all you get besides.
And they are painting the same.
So you got the.
Which is what this one called.
So you got 2000, I don't, you don't, but there's nothing but one computer.
So I don't get Gabe's indexing here.
You had an exhibition in.
And it is not.
It is also being biggest.
So this is how you get the size of the particular map.
So you have good range.
If you leave the board together and look at the write on ones and then you read the value and then you
destroy the value, then you perform a bitwise note and at one you'll be getting.